i^2-2(i)=-1

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Solution for i^2-2(i)=-1 equation: 



i^2-2(i)=-1

We move all terms to the left:

i^2-2(i)-(-1)=0

We add all the numbers together, and all the variables

i^2-2i+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{2}{2}=1$

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